It is known that in RT △ ABC, ∠ a = 90 °, AB > AC, P is a point on AB, ∠ ACP = ∠ B, AC = 6, Pb = 5, find the sine value of ∠ APC. Draw the figure yourself. Please, everyone!
Let AP = x, because ∠ ACP = B, so tan ∠ ACP = Tan ∠ B, that is, AC / AB = AP / AC
So there is 6 / (5 + x) = x / 6, and the solution is x = 4
In RT △ APC, AC = 6, AP = 4, PC = root 52
So sin, ∠ APC = 6 / radical 52 = 3 / radical 13
Choose me!
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