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In the range of 1 / 2 to e, find the definite integral of | LNX |
LNX = 0 means x = 1
∴(1/2,e) = (1/2,1)U(1,e)
∫(1/2,e) |lnx| dx
= ∫(1/2,1) (- lnx) dx + ∫(1,e) lnx dx
= 2 - 2/e
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