Ln (TaNx / 2) / SiNx, how to get indefinite integral
Direct application of partial differential
The original formula = ∫ ln (TaNx / 2) DLN (TaNx / 2)
=(1/2)(lntanx/2)^2 + C
Direct application of partial differential
The original formula = ∫ ln (TaNx / 2) DLN (TaNx / 2)
=(1/2)(lntanx/2)^2 + C