We know the equation x2-2ax + a = 4 about X When we find the value of 1. A, the equation has two positive values? 2. What is the value of a, the equation has two different sign roots, and the absolute value of negative root is larger? 3. What is the value of a when at least one root of the equation is zero?

We know the equation x2-2ax + a = 4 about X When we find the value of 1. A, the equation has two positive values? 2. What is the value of a, the equation has two different sign roots, and the absolute value of negative root is larger? 3. What is the value of a when at least one root of the equation is zero?

X ^ 2 is the square of X, the original equation can be changed to x ^ 2-2ax + A-4 = 0
From (- 2A) ^ 2-4 * (A-4) > 0 to a ^ 2-A + 4 > 0, that is, (A-1 / 2) ^ 2 + 15 / 4 > 0, we can see that no matter what value a is, the equation has two solutions
The formula of the original equation is (x-a) ^ 2 - (a ^ 2-A + 4) = 0, that is, (x-a) ^ 2 = (a ^ 2-A + 4) > 0 (proved above)
So square both sides and move the term to X1 = a + square (a ^ 2-A + 4), X2 = A-Square (a ^ 2-A + 4)
(Note: square (a ^ 2-A + 4) represents the square root of (a ^ 2-A + 4))
1. When X20 is A-Square (a ^ 2-A + 4) > 0, the equation has two positive values, and the solution a is greater than or equal to 4
2. Due to x2