urgent It is known that the vertex of △ ABC is a (0,0) B (4,8) C (6, - 4) point m on the line AB, the tangent vector am = 3MB, the point P on the line AC, and the area of △ APM is the general of △ ABC. The coordinates of point P can be obtained
S△ABC=0.5AB*AC*sinA
S△APM=0.5AM*AP*sinA=0.5S△ABC=0.5*0.5AB*AC*sinA
AP=2AC/3
AP:AC=2:3
(x,y):(6,-4)=2:3
x=4,y=-8/3
P(4,-8/3)
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