We know that vector a = (cos3 / 2x, SIN3 / 2x), vector b = (cosx / 2, - SiNx / 2), and 0 The second question f (x) = (vector a dot multiplied by vector b) - 2 times m multiplied by (absolute value of a + b) The minimum value of F (x) is - 3 / 2, and the value of real number m is obtained

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• 5. In △ ABC, a, B and C are the opposite sides of angles a, B and C respectively. Given vector M = (a, b), vector n = (COSA, CoSb), vector p = (2 √ 2Sin (B + C) / 2,2sina), if vector m ‖ vector n, vector p ^ 2 = 9, we prove that △ ABC is an equilateral triangle
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