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On the sides OA and ob of the triangle OAB, there are two points P and Q respectively. It is known that OP: PA = 1:2, OQ: QB = 3:2, connecting AQ and BP. Let their intersection be r, if the vector OA is vector a and the vector ob is vector B Use vector a and vector B to represent vector or
Let or = xoa + (1-x) OQ = XA + (1-x) (3 / 5) B
OR=yOP+(1-y)OB=y(1/3)a+(1-y)b
We get x = (1 / 3) y ①
(3/5)(1-x)=1-y…… ②
We get x = 1 / 6
so...OR=(1/6)a+(1/2)b
Hee hee Wen Zi, if you're right, add more bonus points_ ∩)O~
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