Put the nine numbers 1 to 9 in the following brackets without repetition to make the formula hold () × () × () = () + ()
1 * 2 * 7 = 5 + 9 8 △ 4 = 6 △ 3 is not easy to answer
RELATED INFORMATIONS
- 1. Fill in the brackets with the numbers 1, 2, 3, 4, 5, 6, 7, 8 and 9 to make the formula tenable and can't be used repeatedly One group: () divide by () = () + () - () = () two groups: () + () - () = () () multiply by () = () () three groups: () () () multiply by () = () ()
- 2. Add a plus sign or a minus sign between every two adjacent numbers of 10, 9, 8, 7, 6, 5, 4, 3, 2, 1 to form an expression with the result of 37. Then the maximum product of these subtractions (numbers with minus sign added in front) is______ .
- 3. Fill in nine numbers from 1 to 9 in (each number is filled in only once) to form three correct formulas
- 4. The following formula is composed of the numbers 1-9, and fill in the appropriate number. 9. () - (). 4 () = (). () 1
- 5. The 10 numbers of 0-9 are filled in 10 & #; to form the following three formulas. (each number can only be used once.) 〾+〾=〾 〾-〾=〾 〾X〾=〾
- 6. Fill in the following blanks without repetition of the nine numbers 1 to 9 to make the formula true ( )x( )x( )=( )+( ) } () divide () = () divide ()
- 7. Put the nine numbers 1 to 9 in the following space to make the formula true ()×()()=()()()=()()×()
- 8. Fill 0 to 9 in the following space respectively to make the formula hold. Each number can only be used once □ + □ = □ + □ = □ + □
- 9. The nine numbers 1-9 shall be filled in the blanks of the following formula respectively, and only one number is allowed to be filled in each blank to make the formula tenable: □
- 10. Fill the seven numbers of 0,1,2,3,7,8,9 in the box to make the formula true □+□=□□-□=□□
- 11. Fill in 1,2,3,4,5,6,7,8,9 in the square so that the formula holds (the number can not be repeated) □ □ □ * □ = □ □ □ □
- 12. Fill the eight numbers 2-9 in the following formula box to make the formula hold
- 13. Put the seven numbers 0, 1, 2, 3, 4, 5 and 6 in the square of the circle. Each number appears just once to form an integer with only one or two digits. What is the number in the square? ○×○=□=○÷○
- 14. Put the seven numbers 0, 1, 2, 3, 4, 5 and 6 in the square of the circle. Each number appears just once to form an integer with only one or two digits. What is the number in the square? ○×○=□=○÷○
- 15. Put the seven numbers 0, 1, 2, 3, 4, 5 and 6 in the square of the circle. Each number appears just once to form an integer with only one or two digits. What is the number in the square? ○×○=□=○÷○
- 16. Put the seven numbers 0, 1, 2, 3, 4, 5 and 6 in the square of the circle. Each number appears just once to form an integer with only one or two digits. What is the number in the square? ○×○=□=○÷○
- 17. Put the seven numbers 0, 1, 2, 3, 4, 5 and 6 in the square of the circle. Each number appears just once to form an integer with only one or two digits. What is the number in the square? ○×○=□=○÷○
- 18. In the following, fill in 1, 2, 3, 4, 5, 6, 7, 8 and 9 (the number in each formula cannot be repeated, and the numerator of fraction part is less than denominator), so that the value of formula a with fraction is the largest and that of formula B is the smallest
- 19. In the following, fill in 1, 2, 3, 4, 5, 6, 7, 8 and 9 (the number in each formula cannot be repeated, and the numerator of fraction part is less than denominator), so that the value of formula a with fraction is the largest and that of formula B is the smallest
- 20. With 4, 5, 6 and 7, which two digit multiplication formula can these four numbers form? What are the minimum product and the maximum product?