Put the seven numbers 0, 1, 2, 3, 4, 5 and 6 in the square of the circle. Each number appears just once to form an integer with only one or two digits. What is the number in the square? ○×○=□=○÷○

Put the seven numbers 0, 1, 2, 3, 4, 5 and 6 in the square of the circle. Each number appears just once to form an integer with only one or two digits. What is the number in the square? ○×○=□=○÷○

It is obvious that the number in the box and the divisor are two digits, and the multiplier and divisor are one digit. It can be seen that 0 is not suitable to be a multiplier, let alone a divisor. Therefore, it is a two digit number, which is the one digit number of the divisor. If the multiplier is 1, no matter what the multiplier is The divisor is the product of three one digit numbers, one of which is 5. There is no 1 in the other two, and there is no 2 (otherwise, 2 × 5 = 10, so the ten digit number of the divisor is the same as the other multiplier). Therefore, the divisor is at least 3 × 4 × 5 = 60. Since there is no number larger than 6, the divisor is 6 0, and the formula is 3 × 4 = 12 = 60 △ 5, so the number in the square is 12