Put the seven numbers 0, 1, 2, 3, 4, 5 and 6 in the square of the circle. Each number appears just once to form an integer with only one or two digits. What is the number in the square? ○×○=□=○÷○

Put the seven numbers 0, 1, 2, 3, 4, 5 and 6 in the square of the circle. Each number appears just once to form an integer with only one or two digits. What is the number in the square? ○×○=□=○÷○

It is obvious that the number in the box and the divisor are two digits, and the multiplier and divisor are one digit. It can be seen that 0 is not suitable to be a multiplier, let alone a divisor