A problem of division of the same base power Given that the x power of 128 is 8 × 2 to the 11th power, find the value of (x-1) to the power of 2008

128=2*2*2*2*2*2*2=2^7
128^x=(2^7)^x=2^7x
8*2^11=2^3*2^11=2^(3+11)=2^14
So 14 = 7x
x=2
So: (x-1) ^ 2008 = (2-1) ^ 2008 = 1 ^ 2008 = 1

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