Given that a straight line passes through points P (2a, 3b) and Q (4b, 6a), and a is not equal to 0, the slope of the straight line is calculated

k=(6a-3b)/(4b-2a)

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1. If we know that a line passes through P (2a, 3b) and Q (4b, 6a) and a is not zero, we can find the slope of the line
2. Given the slope of the straight line k = 1 / 2, P1 (- 2,3), P2 (X2, - 2), P3 (1 / 2, Y3) three points on a straight line, find X2, Y3
3. It is known that the straight line passes through P1 (x1,5), P2 (4, Y2), P3 (- 1, - 3), and the slope of the straight line is - 3
4. If two points P1 (4,9) and P2 (6,3) are known, then the equation for a circle with diameter p1p2 is______ ．
5. Given that the straight line with slope 2 intersects with hyperbola x ^ 2-y ^ 2 = 12 at P1 and P2, find the trajectory equation of the midpoint of line p1p2
6. Given the hyperbola x ^ 2-y ^ 2 / 2 = 1, the line L passing through point a (2,1) intersects with the given hyperbola at two points P1 and P2, and the trajectory equation of point P in line p1p2 is obtained
7. A straight line L passing through the point (- 5, - 4) intersects two coordinate axes and is tangent to the triangle formed by the two axes. The area of the triangle is 5. The equation of L is obtained . urgent
8. If the line L passes through the point P (3,2), and the midpoint of the line cut by the coordinate axis is exactly P, the equation of the line L is obtained
9. A straight line passes through the point (1.3), which is exactly the midpoint of the line cut by the two coordinate axes
10. If the point P (- 1.3) is the midpoint of the line L cut by two axes, the equation of the line is obtained
11. It is known that the slope k of the straight line L is obtained through two points P1 (2,1) P2 (m, 2) (m ∈ R), and the inclination angle a of L and its value range are obtained?
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15. If a straight line passes through the point P (- 5, - 4) and the area of the triangle enclosed by the two coordinate axes is 5, the equation of the straight line is obtained
16. Solve the linear equation of point P (- 5,4) which is surrounded by two coordinate axes and has a triangle area of 5
17. When crossing point a (- 5, - 4) on a straight line L, it intersects two coordinate axes and the area of the triangle enclosed by the two axes is 5, the equation for solving the straight line L is obtained 1. Let the slope of the line be K y+4=k(x+5) x=0,y=5k-4 y=0,x=4/k-5=(4-5k)/k So area = | 5k-4 | * | (4-5k) / K} / 2 = 5 |(5k-4)^2/k|=10 (5k-4)^2=±10k 25k^2-40k+16=±10k -No solution at 10K 25k^2-50k+16=0 (5k-8)(5k-2)=0 k=8/5,k=2/5 8x-5y+20=0 2x-5y-10=0 Or? 2. Let y = KX + 5k-4. (k is not equal to 0) Let y = 0, x = (4-5k) / K Let x = 0.y = 5k-4 S = 1 / 2 * {5k-4} * {(4-5k) / K} ({} is absolute value.) Let k > 4 / 5, then (5k-4) ^ 2 / k = 10, k = 8 / 5, k = 2 / 5 (rounding) Then y = 8 / 5x + 4 When 0
18. Make a straight line L through point a (- 5, - 4) so that it intersects with the two coordinate axes and the area of the triangle enclosed by the two axes is 5
19. Make a straight line L through the point P (- 5, - 4) so that it intersects with the two coordinate axes and the area of the triangle enclosed by the two axes is 5, and solve the linear equation It's better not to use slope,
20. Find the equation of the line L whose area is 4 and slope is - 2