Make a straight line L through point a (- 5, - 4) so that it intersects with the two coordinate axes and the area of the triangle enclosed by the two axes is 5

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• 1. When crossing point a (- 5, - 4) on a straight line L, it intersects two coordinate axes and the area of the triangle enclosed by the two axes is 5, the equation for solving the straight line L is obtained 1. Let the slope of the line be K y+4=k(x+5) x=0,y=5k-4 y=0,x=4/k-5=(4-5k)/k So area = | 5k-4 | * | (4-5k) / K} / 2 = 5 |(5k-4)^2/k|=10 (5k-4)^2=±10k 25k^2-40k+16=±10k -No solution at 10K 25k^2-50k+16=0 (5k-8)(5k-2)=0 k=8/5,k=2/5 8x-5y+20=0 2x-5y-10=0 Or? 2. Let y = KX + 5k-4. (k is not equal to 0) Let y = 0, x = (4-5k) / K Let x = 0.y = 5k-4 S = 1 / 2 * {5k-4} * {(4-5k) / K} ({} is absolute value.) Let k > 4 / 5, then (5k-4) ^ 2 / k = 10, k = 8 / 5, k = 2 / 5 (rounding) Then y = 8 / 5x + 4 When 0
• 2. Solve the linear equation of point P (- 5,4) which is surrounded by two coordinate axes and has a triangle area of 5
• 3. If a straight line passes through the point P (- 5, - 4) and the area of the triangle enclosed by the two coordinate axes is 5, the equation of the straight line is obtained
• 4. Given P1 (- 1, a), P2 (3, 6) and the slope of p1p2 k = 2, | p1p2 | =? To find the detailed explanation
• 5. P1 (x1, Y1) P2 (X2, Y2) are two points on a straight line with a slope of K Prove that ip1p2i = 1 + k * 2 times ix1-x2i = 1 + k * 2 times (x1 + x2) - 4x1x2 I is the vertical line, ip1p2i is the absolute value of p1p2, and ix1-x2i is the absolute value of x1-x2
• 6. Given the slope of the straight line k = 2, P1 (3,5), P2 (x2,7), P3 (- 1, Y3) are the three points on the straight line, find X2, Y3 Does anyone know
• 7. It is known that the slope k of the straight line L is obtained through two points P1 (2,1) P2 (m, 2) (m ∈ R), and the inclination angle a of L and its value range are obtained?
• 8. Given that a straight line passes through points P (2a, 3b) and Q (4b, 6a), and a is not equal to 0, the slope of the straight line is calculated
• 9. If we know that a line passes through P (2a, 3b) and Q (4b, 6a) and a is not zero, we can find the slope of the line
• 10. Given the slope of the straight line k = 1 / 2, P1 (- 2,3), P2 (X2, - 2), P3 (1 / 2, Y3) three points on a straight line, find X2, Y3
• 11. Make a straight line L through the point P (- 5, - 4) so that it intersects with the two coordinate axes and the area of the triangle enclosed by the two axes is 5, and solve the linear equation It's better not to use slope,
• 12. Find the equation of the line L whose area is 4 and slope is - 2
• 13. Given that the slope of the line L is 16, and the line and the two coordinate axes form a triangle with an area of 3, then the equation of the line L is______ ．
• 14. If the ordinate of the intersection of the line y = KX + B and the line y = 12x + 3 is 5, and the abscissa of the intersection of the line y = 3x-9 is 5, then the area of the triangle formed by the line y = KX + B and the two coordinate axes is () A. 32B. 52C. 1D. 12
• 15. Find the linear equation that is perpendicular to the line 3x-4y + 7 = 0 and the circumference of the triangle enclosed with the coordinate axis is 10
• 16. It is known that the line L1 is perpendicular to the line l2:3x-4y-7 = 0, and the circumference of the triangle formed by the line L1 and the two coordinate axes is 10, Find the point normal equation of line L1
• 17. Find the linear equation perpendicular to 3x-4y-7 = 0, and the circumference of the triangle surrounded by two coordinate axes is 12
• 18. 5. The linear equation of a triangle perpendicular to 3x-4y = 7 and with a circumference of 10 formed by two coordinate axes is?
• 19. Find the equation of the line L with circumference 24, which is perpendicular to 3x + 4y-12 = 0 and surrounded by two coordinate axes
• 20. It is known that the equation of the line L is 3x + 4y-12 = 0. The equation of the line L 'is solved so that the triangle area bounded by L' and l 'is 6