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It is known that the line L1 is perpendicular to the line l2:3x-4y-7 = 0, and the circumference of the triangle formed by the line L1 and the two coordinate axes is 10, Find the point normal equation of line L1
Kl2 = 3 / 4, so kl1 = - 4 / 3 let: y = KX + B, then: y = - 4 / 3x + B when y = 0: x = 3 / 4B (a right angle side) when x = 0: y = B (another right angle side) by Pythagorean theorem: the hypotenuse formed with the coordinate axis = 5 / 4b is known: 3 / 4B + B + 5 / 4B = 10, then: B = 10 / 3, so y = - 4 / 3x + 10 / 3
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