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If the ordinate of the intersection of the line y = KX + B and the line y = 12x + 3 is 5, and the abscissa of the intersection of the line y = 3x-9 is 5, then the area of the triangle formed by the line y = KX + B and the two coordinate axes is () A. 32B. 52C. 1D. 12
Substituting y = 5 into y = 12x + 3 to get 12x + 3 = 5, the solution is x = 4, that is, the intersection coordinates of y = KX + B and y = 12x + 3 are (4,5); substituting x = 5 into y = 3x-9 to get y = 6, that is, the intersection coordinates of y = KX + B and y = 3x-9 are (5,6); substituting (4,5) and (5,6) into y = KX + B to get 4K + B = 55k + B = 6
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