5. The linear equation of a triangle perpendicular to 3x-4y = 7 and with a circumference of 10 formed by two coordinate axes is?
Let 4x + 3Y = M
Let x, y = 0 in turn
Right angle side length
|m/4|
|m/3|
So the slant side is long
|5m/12|
So (perimeter + rise, discuss m plus minus)
m=±1
answer:
4x+3y-1=0
or
4x+3y+1=0
The process is as if I was weeding
RELATED INFORMATIONS
- 1. Find the linear equation perpendicular to 3x-4y-7 = 0, and the circumference of the triangle surrounded by two coordinate axes is 12
- 2. It is known that the line L1 is perpendicular to the line l2:3x-4y-7 = 0, and the circumference of the triangle formed by the line L1 and the two coordinate axes is 10, Find the point normal equation of line L1
- 3. Find the linear equation that is perpendicular to the line 3x-4y + 7 = 0 and the circumference of the triangle enclosed with the coordinate axis is 10
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- 6. Find the equation of the line L whose area is 4 and slope is - 2
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- 13. What is the area of the triangle formed by the line 3x-4y-12 = 0 and the two axes?
- 14. It is known that the equation of line L is 3x + 4y-12 = 0. The equation of line L 'is: l' is perpendicular to L, and the area of triangle enclosed by L 'and coordinate axis is 4
- 15. Given that the line L is parallel to the line 3x + 4Y = 0 and the area of the triangle surrounded by the two coordinate axes is 24, then the linear equation is?
- 16. Given that the inclination angle of line L is equal to 3x + 4y-7 = 0, and the area of triangle enclosed by two coordinate axes is equal to 24, the equation of line L is obtained
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