It is known that the equation of line L is 3x + 4y-12 = 0. The equation of line L 'is: l' is perpendicular to L, and the area of triangle enclosed by L 'and coordinate axis is 4

It is known that the equation of line L is 3x + 4y-12 = 0. The equation of line L 'is: l' is perpendicular to L, and the area of triangle enclosed by L 'and coordinate axis is 4

Let L 'be y = KX + B
∵ L 'is perpendicular to the line L: 3x + 4y-12,
The slope of L 'is k = - 4 / 3
The line L 'is y = - 4x / 3 + B
When x = 0, y = IBI; when y = 0, x = 3ibi / 4
S=(3IbI/4)*IbI/2=4
b^2=8/3
∴b=±2√6/3
The line L 'is y = - (4x / 3) + 2 √ 6 / 3, y = - (4x / 3) - 2 √ 6 / 3