(SiNx + cosx) / (SiNx cosx) = 2, then sinxcosx =?

(SiNx + cosx) / (SiNx cosx) = 2, then sinxcosx =?

sinx+cosx=2sinx-2cosx
sinx=3cosx
sin²x=9cos²x
Because Sin & sup2; X + cos & sup2; X = 1
So cos & sup2; X = 1 / 10
sinxcosx
=(3cosx)cosx
=3cos²x
=3/10