Given the vector α = (cosx, SiNx), B = (√ 2, √ 2), a · B = 8 / 5, then the value of Tan (x - π / 4) is

Given the vector α = (cosx, SiNx), B = (√ 2, √ 2), a · B = 8 / 5, then the value of Tan (x - π / 4) is

ab=√2cosx+√2sinx=8/5
SiNx + cosx = (4 / 5) √ 2
So (SiNx + cosx) ^ 2 = 32 / 25
That is, 1 + 2sinxcosx = 32 / 25, then 2sinxcosx = 7 / 25
Then (SiNx cosx) ^ 2 = 1-2sinxcosx = 1-7 / 25 = 18 / 25
SiNx cosx = ± (3 / 5) √ 2
tan(x-π/4)=(tanx-1)/(tanx+1)=(sinx-cosx)/(sinx+cosx)
=[±(3/5)√2]/[(4/5)√2]
=±3/4