1. The number of solutions of the equation x ^ 2-x = LNX is 2. Given that the function f (x) = 4 ^ x + k * 2 ^ x + 1 has only one zero point, then the zero point is 1. The number of solutions of the equation x ^ 2-x = LNX is 2. Given that the function f (x) = 4 ^ x + k * (2 ^ x) + 1 has only one zero point, then the zero point is

1. The number of solutions of the equation x ^ 2-x = LNX is 2. Given that the function f (x) = 4 ^ x + k * 2 ^ x + 1 has only one zero point, then the zero point is 1. The number of solutions of the equation x ^ 2-x = LNX is 2. Given that the function f (x) = 4 ^ x + k * (2 ^ x) + 1 has only one zero point, then the zero point is

1. Draw an image to get two solutions
2. Let t = 2 ^ x, so T ^ 2 + KT + 1 = 0, because this equation has only one solution, so K ^ 2-4 = 0, k = 2 or - 2
When k = 2, t = - 1, it does not match, so it is discarded
When k = - 2, t = 1, so 2 ^ x = 1, x = 0, so zero is 0