If the line y = x is the tangent of the curve y = x3-3x2 + ax, then a=______ ．

If the line y = x is the tangent of the curve y = x3-3x2 + ax, then a=______ ．

Pointpointpointpointp (x0, x0) P (x0, x0) pointpointpointp (P (x0, x0, x0) P (P (x0, x0, x0, x0, x0) P (P (x0, x0, x0, x0) straight line y = x is the curve y = x = x is the tangent of y = x3-3x3-3x2-3x2-3x2 + ax, the tangent of the tangent line, the slope of the tangent line is 1-1 \μ the slope of the slope of the tangent line, the slope of the tangent is 1 \
the curve, point P on the curve, point point P on the curve, point point P on the curve, x03-3-3-3-3x03-3x03-3-3x02-3x02-3x02-3x02 + 0-3-3x02 + ax0-3x02 + 0 2 + 0 + 0 + 0 = 0 = 0 2 (the solution of - 3x0 = 3x02-6x0 is x0 = 0 or 32 In conclusion, the value of a is 1 or 134