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Given SiNx + siny = cosx + cosy = 1 / 2007, what is SiNx + cosx = then
siny=1/2007-sinx
cosy=1/2007-cosx
Add the square of both sides of the above two formulas to get the
（siny）^2+（cosy）^2=2/（2007^2）-2（sinx+cosx）/2007+（sinx）^2+（cosx）^2
Because (siny) ^ 2 + (cosy) ^ 2 = 1, (SiNx) ^ 2 + (cosx) ^ 2 = 1
obtain
sinx+cosx=1/2007
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