If the distance between any point on the circle (x-1) ^ 2 + (Y-1) ^ 2 = R ^ 2 (r > 0) and the origin is 1, the value range of R can be obtained

The center O is (1,1), and the distance between the center and the origin is √ 2
For the convenience of explanation, suppose y = x intersects with circle a and B, the center of circle is on it, and a is the point close to the origin. Just pay attention to the special position of A
Only √ 2-1 ≤ R ≤ √ 2 + 1

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