Given SiNx + siny = 1 / 3, find the maximum and minimum of SiNx cosy * cosy

Given SiNx + siny = 1 / 3, find the maximum and minimum of SiNx cosy * cosy

SiNx = 1 / 3-siny, so SiNx - (cosy) ^ 2 = (1 / 3-siny) - [1 - (siny) ^ 2] = (siny) ^ 2-siny-2 / 3 = (siny-1 / 2) ^ 2-1 / 4-2 / 3siny ∈ [- 1,1]. When siny = - 1, (siny-1 / 2) ^ 2 obtains the maximum value of 9 / 4, and SiNx - (cosy) ^ 2 obtains the maximum value of 4 / 3