Simplification of COS (a - π) cot (5 π - a) / sin (- 2 π - a) The answer is the square of - COTA,

RELATED INFORMATIONS

• 1. Simplification of cos α + cot α / 1 + sin α
• 2. Simplification [cos (α - π) * cot (5 π - α)] / [sin (- 2 π - α)] ② (1 + cot & # 178; E) (E is the third quadrant angle)
• 3. The result of simplifying sin (2 π - a) cot (π + a) / cos (π - a) is
• 4. (1-tan α) / (1 + Tan α) = 3-2 √ 2 find the value of [(sin α + cos α) ^ 2-1] / (cot α - sin α times cos α)
• 5. Sin Θ - cos Θ = 1 / 2, find Tan Θ + cot Θ
• 6. Sin θ - cos θ = 1 / 2, then Tan θ + cot θ=
• 7. Sin θ / radical (1-sin & sup2; θ) + radical (1-cos & sup2; θ) / cos θ Theta belongs to (3 π / 2,2 π)
• 8. Given Tan α + cot α = 52, α ∈ (π 4, π 2), find the values of COS 2 α and sin (2 α + π 4)
• 9. Given Tan α + cot α = 52, α ∈ (π 4, π 2), then Cos2 α = 1___ ．
• 10. 15(sin2θ + cos2θ) × 37(sin2π + cos2π) = 0
• 11. Simplify (COS ^ 2 α - Sin ^ 2 β) / (sin ^ 2 α * sin ^ 2 β) - cot ^ 2 α cot ^ 2 β
• 12. It is known that 2sin2 α + 2Sin α cos α 1 + Tan α = K (0 ＜ α＜ π 2)
• 13. If Tan α = 4, then 2Sin α & sup2; + sin α cos α + 3 =?
• 14. Given Tan α = 2, find the value of Sin & sup2; α + 2Sin α cos α + 2?
• 15. Given that the distance from a point P on the hyperbola X & # 178 / 36-y & # 178 / 64 = 1 to a focus of the hyperbola is equal to 9, find the perimeter of △ pf1f2
• 16. If the distance from point P to the right focus on the hyperbola x213-y212 = 1 is equal to 13, then the distance from point P to the right collimator is () A. 135B. 13C. 5D. 513
• 17. Knowledge of triangles In the triangle ABC, BC = a, AC = B, ab = C. if the triangle ABC is not a right triangle, but an acute triangle or an obtuse triangle, please analogy Pythagorean theorem, try to guess the relationship between the sum of squares of a and B and the square of C, and explain the reason
• 18. Sin = contrast skew cos = neighborhood skew Tan = contrast skew can only be used in right triangles or all triangles
• 19. Sin equals to contrast, cos equals to neighbor and Tan cot. how can I remember them well? I always forget them
• 20. In △ ABC, ∠ a + ∠ C = ∠ B, then △ ABC is______ A triangle