Sin θ - cos θ = 1 / 2, then Tan θ + cot θ=

Sin θ - cos θ = 1 / 2, then Tan θ + cot θ=

The solution of sin θ - cos θ = 1 / 2 is as follows: (sin θ - cos θ) &# 178; = 1 / 4, i.e. 1-2sin θ cos θ = 1 / 4  2Sin θ cos θ = 3 / 4  sin θ cos θ = 3 / 8tan θ + cot θ = (sin θ / cos θ) + (COS θ / sin θ) = (Sin & # 178; θ + cos & # 178; θ) / (sin θ cos θ) = 1 / (3 / 8) = 8 / 3