If Tan α = 4, then 2Sin α & sup2; + sin α cos α + 3 =?
tanα=sinα/cosα=4
So sin α = 4cos α
cosα²+sinα²=17cosα²=1 cosα²=1/17
2sinα ²+sinαcosα+3
=2+2cosα²+3
=5+2cosα²
=5+2/17
=87/17
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