Why is Tan ^ 2 [(B + C) / 2] = Tan ^ 2 (π - a) / 2 = cot ^ 2 (A / 2) in the acute triangle ABC

Why is Tan ^ 2 [(B + C) / 2] = Tan ^ 2 (π - a) / 2 = cot ^ 2 (A / 2) in the acute triangle ABC

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