It is known that α is an acute angle
sinα+cosα
=√2(√2/2sinα+√2/2cosα)
=√2(cos45 sinα+sin45 cosα)
=√2sin(α+45)
0
RELATED INFORMATIONS
- 1. It is known that θ is a positive acute angle, and sin θ + cos θ is proved Sin θ + cos θ = sin (θ + 45 °) twice the root sign
- 2. Let α be an acute angle and prove: sin α + cos α
- 3. It is known that the angle α is an acute angle
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- 5. Basic knowledge of triangle The school has a piece of green space. First, I plan to start from the position indicated by point d (BD: DC = 2:1). I hope the green space on both sides of the small ditch is equal. Now D is not the midpoint of BC. How can I divide the green space into two equal blocks and pass through point d?
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- 7. Why is Tan ^ 2 [(B + C) / 2] = Tan ^ 2 (π - a) / 2 = cot ^ 2 (A / 2) in the acute triangle ABC
- 8. In the triangle ABC, M is the midpoint of B and C. The three (1) of the triangle AMC determine the shape of the triangle (2) find that the COSA edge is three consecutive integers and Tanc = cotb In the triangle ABC, M is the midpoint of B and C, and the three sides of AMC are three consecutive integers and Tanc = cotbam. 1) judge the shape of the triangle. (2) find out that the COSA side is three consecutive integers and Tanc = cot
- 9. In △ ABC, ∠ a + ∠ C = ∠ B, then △ ABC is______ A triangle
- 10. Sin equals to contrast, cos equals to neighbor and Tan cot. how can I remember them well? I always forget them
- 11. It is proved that: (1-sin2 α) / (Cos2 α) = (1-tan α) / (1 + Tan α)
- 12. Given Tan α = 1 / 2, find Sin & # 178; α - cos & # 178; α=
- 13. If sin (a + b) = 1, then Tan (2a + b) + tanb
- 14. If sin (a + b) = 1, then Tan (2a + b) + tanb =?
- 15. Sin (2a + b) + 2sinb = 0, Tan a = 3, Tan (a + b) ``
- 16. Given sin (2a + b) = 2sinb, prove Tan (a + b) = 3tana
- 17. Given 2sinb = sin (2a + b), find the value of Tan (a + b) to tanb
- 18. Given Tan (π / 4 + a) = 1 / 5, find the value of (sin2a sin ^ a) / (1-cos2a)
- 19. Given Tan (45 + a) = 3, find the value of sin2a-2cos ^ a
- 20. Find the value of sin2a-2cos ^ 2a-1 with known Tan (π / 4 + a) = 3 I've worked out Tana = 1 / 2 In addition, sin2a-cos2a-1 is reduced to sin2a-cos2a-1-1