Given sin (2a + b) = 2sinb, prove Tan (a + b) = 3tana

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• 1. Sin (2a + b) + 2sinb = 0, Tan a = 3, Tan (a + b) ``
• 2. If sin (a + b) = 1, then Tan (2a + b) + tanb =?
• 3. If sin (a + b) = 1, then Tan (2a + b) + tanb
• 4. Given Tan α = 1 / 2, find Sin & # 178; α - cos & # 178; α=
• 5. It is proved that: (1-sin2 α) / (Cos2 α) = (1-tan α) / (1 + Tan α)
• 6. It is known that α is an acute angle
• 7. It is known that θ is a positive acute angle, and sin θ + cos θ is proved Sin θ + cos θ = sin (θ + 45 °) twice the root sign
• 8. Let α be an acute angle and prove: sin α + cos α
• 9. It is known that the angle α is an acute angle
• 10. Simplifying a & sup2; SIN3 / π + B & sup2; Cos π / 6-absin π / 4cos π / 4tan π / 3 + abcos π / 6 = process
• 11. Given 2sinb = sin (2a + b), find the value of Tan (a + b) to tanb
• 12. Given Tan (π / 4 + a) = 1 / 5, find the value of (sin2a sin ^ a) / (1-cos2a)
• 13. Given Tan (45 + a) = 3, find the value of sin2a-2cos ^ a
• 14. Find the value of sin2a-2cos ^ 2a-1 with known Tan (π / 4 + a) = 3 I've worked out Tana = 1 / 2 In addition, sin2a-cos2a-1 is reduced to sin2a-cos2a-1-1
• 15. Given Tan (π / 4 + a) = 3, find the value of sin2a-2cos square a
• 16. It is known that Tan (a pie / 4) = 1 / 2 and - Pie / 2
• 17. Given Tan a = - 1 / 3, find sin2a cos ^ 2A
• 18. Given Tan (a + π / 4) = - 1 / 2, π / 2 & lt; a & lt; π, find the value of (sin2a-2cos ^ 2a) / √ 2Sin (a - π / 4)
• 19. It is known that Tan (a + 45) = - 1 / 2, (90
• 20. Given that Tan (π / 4-A) = 1 / 3, a belongs to (0, π / 4). (1) find the value of (a) = (sin2a-2cos ^ 2a) / (1 + Tana) (2) If B belongs to (0, π / 2), and sin (3 π / 4 + b) = - radical 5 / 5, find the value of a + B