Given Tan (π / 4 + a) = 1 / 5, find the value of (sin2a sin ^ a) / (1-cos2a)

Let B = π / 4. - > Tan (a + b) = (Tana - tanb) / (1 + Tana - tanb) = 1 / 5 - > (Tana - 1) / (1 + Tan a) = 1 / 5 - > Tan a = 3 / 2. (sin2a - Sin ^ 2a) / (1-cos2a) = (2cosa sin a - Sin ^ 2 (a)) / (1 - (1 - 2Sin ^ 2 (a))) =

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