It is proved that: (1-sin2 α) / (Cos2 α) = (1-tan α) / (1 + Tan α)

It is proved that: (1-sin2 α) / (Cos2 α) = (1-tan α) / (1 + Tan α)

(1-tanα)/(1+tanα) =(1-sinα/cosα)/(1+sinα/cosα)=((cosα-sinα)/cosα)/((cosα+sinα)/cosα)=(cosα-sinα)/(cosα+sinα)=((cosα-sinα)*(cosα-sinα))/((cosα+sinα)(cosα-sinα))=(cosα*cosα...