Sin (2a + b) + 2sinb = 0, Tan a = 3, Tan (a + b) ``

Sin (2a + b) = sin (a + b) * cosa + Sina * cos (a + b); SINB = sin (a + B-A) = sin (a + b) * cosa cos (a + b) * Sina; substituting sin (2a + b) + 2sinb = 0:3 * sin (a + b) * cosa cos (a + b) Sina = 0 (*) as long as cosa and COS (a + b) are not zero, the conclusion can be drawn from the formula (*)

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