If the image of a given function passes through points a (- 1,3) and B (2, - 3), (1) find the analytic formula of a function, (2) judge point C (- 2,5) Why substitute - 3 = 2K + B instead of 3 = - K + B? For example, the following solution 1. Let the analytic expression of a function be y = KX + B, Because the function image passes through the points a (- 1,3) and B (2, - 3), the value of the two coordinate points is substituted into the analytic formula of the function to obtain k = - 2, B = 1, that is, the analytic formula is y = - 2x + 1 | Math enthusiast | Mathematical art

If the image of a given function passes through points a (- 1,3) and B (2, - 3), (1) find the analytic formula of a function, (2) judge point C (- 2,5) Why substitute - 3 = 2K + B instead of 3 = - K + B? For example, the following solution 1. Let the analytic expression of a function be y = KX + B, Because the function image passes through the points a (- 1,3) and B (2, - 3), the value of the two coordinate points is substituted into the analytic formula of the function to obtain k = - 2, B = 1, that is, the analytic formula is y = - 2x + 1

Let the first-order function be y = KX + B
Because the image passes through (- 1,3) (2, - 3)
So we substitute x = - 1, y = 3; and x = 2, y = - 3 into y = KX + B respectively
We obtain: 3 = - K + B and - 3 = 2K + B
The solution of the above binary linear equations is: k = - 2, B = 1
So the primary function is y = - 2x + 1

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