Given the linear function y = - 1 / 2x + 2, if the point m is a point on the function image in the second quadrant, and the distance from the point m to the X axis is twice the distance from the point m to the Y axis, the coordinates of the point m are obtained

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• 1. 1. The quadrant that the image of a function y = - 5x + 3 passes through is? 2. If the image of a function y = 2x + 4 passes through a point (m, 8), then M =?
• 2. The image of a linear function is parallel to the straight line y = - 5x + 4 and intersects with the image of the function y = 2 / X at the point m (- 2, m) 1) Finding the value of M 2) Find the analytic expression of this first-order function 3) If the image of a linear function intersects the y-axis at point B, the area of △ OBM is calculated
• 3. Is there a relationship between hyperbola and graph of first order function? What's the difference between a first-order function and an inverse proportion function? Not all of them have y increasing with X or Y decreasing with X. why do we have an inverse proportion function when we have a first-order function? Can't we all use a first-order function?
• 4. When the value of the first-order function is greater than that of the inverse scale function, the image of the first-order function is above the hyperbola. What does this mean ditto
• 5. Function y = - 3x + 4 the coordinate of the intersection of function image and X axis is, and the coordinate of the intersection of function image and Y axis is
• 6. If y = (m-2) x + (M2-4) is a positive proportional function, then the value of M is () A. 2B. - 2C. ± 2D. Any real number
• 7. If y = (m-2) x ^ m ^ 2 is a positive proportion function, then M=__ Function. The analytic expression is__ . y = (m-2) x + M-3 is a positive proportional function, then M=__ . analytic expression__ .
• 8. If the function y = (m-2) x + 5-m is a positive proportional function, then the value of M is (), and the analytic expression of this function is ()
• 9. Given that the image of positive scale function passes through M (3,2) and n (m, - 6), the analytic expression of the function and the value of M are obtained emergency
• 10. Is a positive proportional function, y decreases with the increase of X. find m and the analytic expression of the function
• 11. Given the square of a function y = - 2x, how to translate the image of this function so that it can pass through (0,0) and (1,6) points
• 12. When we know the square of the first-order function y = (2m-1) x (3m) - (n + 2), m and N, the image is a straight line passing through (0,4)
• 13. The image of a function passes through point a (- 1,3) and point (2,3), the analytic expression of the function is obtained, and whether point C (- 2,5) is on the image of the function is judged
• 14. Given that the image of a function passes through both points (1,2) and (- 1,8) 1, find the analytic expression. 2. Judge whether the point (2, - 1) is on the analytic expression of the function
• 15. If the image of a given function passes through points a (0.3) B (2, - 3) (1), find the analytic expression of the function (2) and judge whether point C (- 2.8) is on the image of the function
• 16. Given that the image of a function of degree passes through the point A. (0,8) B (- 4,0), find the analytic expression of the function
• 17. If the image of the first-order function is known to pass through the points (- 2,7), (0,3), find the analytic formula of the function, and judge whether the point a (0.5,2) is on the line
• 18. It is known that the image of a function passes through two points (3,5) and (- 4, - 9), and (1) the analytic expression of the function is obtained. (2) if the point (a, 2) is on the function image,
• 19. If the image of a given function passes through points a (- 1,3) and B (2, - 3), (1) find the analytic formula of a function, (2) judge point C (- 2,5) Why substitute - 3 = 2K + B instead of 3 = - K + B? For example, the following solution 1. Let the analytic expression of a function be y = KX + B, Because the function image passes through the points a (- 1,3) and B (2, - 3), the value of the two coordinate points is substituted into the analytic formula of the function to obtain k = - 2, B = 1, that is, the analytic formula is y = - 2x + 1
• 20. If the image of a function of degree is known, the analytic expression of the function can be obtained through points a (0,3) and B (2, - 3) (1)