Given that the ellipse x ^ 2 / 9 + y ^ 2 / 5 = 1 passes through the right focus F, makes a chord intersection ellipse not perpendicular to the x-axis at two points AB, and the vertical bisector of AB intersects the x-axis at n, then NF is equal to ab

Given that the ellipse x ^ 2 / 9 + y ^ 2 / 5 = 1 passes through the right focus F, makes a chord intersection ellipse not perpendicular to the x-axis at two points AB, and the vertical bisector of AB intersects the x-axis at n, then NF is equal to ab

Let the slope of the straight line be 1. The right focus f (2,0). The equation of the straight line AB is y = X-2. The simultaneous equations {X29 + Y25 = 1y = X-2, substituting y = X-2 into X29 + Y25 = 1, and arranging it into 14x2-36x-9 = 0. Let a (X1, Y1), B (X2, Y2), then X1 + x2 = 187, Y1 + y2 = x1-2 + x2-2 = - 107, x1x2 = - 914,... AB sit at the middle point