Given that the ellipse x 2 / 4 + y 2 / 3 = 1 passes through the left focus of the ellipse and is parallel to the vector V = (1,1), the ellipse intersects two points a and B, and the length of the chord AB is calculated
Because a ^ 2 = 4, B ^ 2 = 3, so, C ^ 2 = a ^ 2-B ^ 2 = 1, then the left focus is (- 1,0), the equation of line AB is y = x + 1, substituting it into the elliptic equation to get x ^ 2 / 4 + (x + 1) ^ 2 / 3 = 1, simplifying to 7x ^ 2 + 8x-8 = 0, let a (x1, Y1), B (X2, Y2), then X1 + x2 = - 8 / 7, X1 * x2 = - 8 / 7, so | ab | ^ 2 = (x2-x
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- 1. If the line passing through the origin and the ellipse * * are the left focus of the ellipse, then the maximum area of the triangle ABF is If f (- C, 0) is the left focus of the ellipse, then the maximum area of the triangle ABF is A. The square of BC B, AB C, AC D, B
- 2. Through the focus F of the ellipse x ^ 2 / 4 + y ^ 2 = 1, make the chord AB, and find the maximum area of the triangle AOB (o is the coordinate origin) Ask for detailed explanation
- 3. Let AB be the chord of the center of the ellipse x ^ 2 / 9 + y ^ 2 / 25 = 1, and f be a focal point of the ellipse, then the maximum area of the triangle ABF is
- 4. If AB is the chord passing through the center of the ellipse x2 / 25 + Y2 / 16 = 1 and F1 is the focus of the ellipse, then the area of the triangle f1ab is the largest Method 2 (basic method): s △ f1ab = s △ oaf1 + s △ obf1 = (C × y1-y2) × 2 = (3 × y1-y2) × 2 Case (1): when k exists, let AB: y = KX be substituted into the ellipse x2 / 25 + Y2 / 16 to find y1-y2, and get 60 × √ K square × √ [25 × K square × 16] / (25 × K square × 16) < 12 Case (2): when K does not exist, s = B × 2C △ 2 = 12 According to (1) (2), s ≤ 12 My formula is 60 ×√ K square × √ [25 × K square + 16] / (25 × K square + 16), then I get 15,
- 5. If AB is the chord passing through the center of the ellipse x2 / A + Y2 / B2 = 1 and F1 (C, 0) is the focus of the ellipse, then the area of the triangle f1ab is the maximum
- 6. Given that P is any point on the ellipse x ^ 2 / 4 + y ^ 2 = 1, F1 and F2 are the two focuses of the ellipse, find the minimum value of absolute value Pf1 ^ 2 + absolute value PF2 ^ 2
- 7. If P is on the ellipse, and (absolute value of Pf1) - (P It is known that the two focal points of ellipse are F1 (0, - 1) F2 (0,1) eccentricity e = 1 / 2 Find 1. Elliptic equation 2. If P is on the ellipse and (absolute value of Pf1) - (absolute value of PF2) = 1, find the cos angle f1pf2
- 8. The focus F1, F2 and point P of the ellipse x ^ 2 / 9 + y ^ 2 / 2 = 1 are on the ellipse. If the absolute value of Pf1 = 2 ~ then the absolute value of PF2 = angle f1pf2, the size of PF2 is
- 9. Let p be a point on the ellipse x ^ 2 / 5 + y ^ 2 / 25 = 1, and F1 and F2 be the two focuses of the ellipse. If Pf1 ⊥ PF2, then the absolute value of the difference between Pf1 and PF2 A.0 B.2√5 C.4√5 D.2√15
- 10. If AB is the chord passing through the center of the ellipse X & # 178 / 25 + Y & # 178 / 16 and F1 is the left focus, then the maximum area of △ Abf1 is___ 12___ ,
- 11. Through the left focus F of the ellipse x ^ 2 / 36 + y ^ 2 / 27 = 1, make a chord AB that is not perpendicular to the major axis. If the vertical bisector of AB intersects the X axis at n, then FN / ab=
- 12. Given that the ellipse x ^ 2 / 9 + y ^ 2 / 5 = 1 passes through the right focus F, makes a chord intersection ellipse not perpendicular to the x-axis at two points AB, and the vertical bisector of AB intersects the x-axis at n, then NF is equal to ab
- 13. Through the right focus F2 of the ellipse x ^ 2 / 4 + y ^ 2 / 3 = 1, make a straight line with an inclination angle of pi / 4 to intersect the ellipse and two points a and B. find the length of the chord ab
- 14. If a straight line passing through the left focus of the ellipse x ^ 2 + 2Y ^ 2 = 4 with a left inclination angle of 30 degrees intersects the ellipse at two points a and B, the chord length AB will be obtained=
- 15. Quasilinear equation of ellipse and hyperbola
- 16. How to judge the positive and negative of Quasilinear equation of ellipse and hyperbola? The Quasilinear equation of ellipse and hyperbola is: x = ± a ^ 2 / C How to judge positive and negative?
- 17. What are the properties of quasars of ellipses and hyperbolas
- 18. A hyperbola with the same asymptote as x ^ 2 / 4 - y ^ 2 = 1 is A.y^2/4 - x^2=1 B.x^2/16 - y^2/8=1 C.x^2/4 - y^2=-2 D.x^2/4 + y^2=1
- 19. What is the Quasilinear equation of ellipse and hyperbola? How many quasilinear equations are there?
- 20. It is known that the eccentricity of hyperbola x2a2-y2b2 = 1 is 2, and the focus is the same as that of ellipse X225 + Y29 = 1, then the focus coordinates and asymptote equations of hyperbola are () A. (±4,0),y=±33xB. (±4,0),y=±3xC. (±2,0),y=±33xD. (±2,0),y=±3x