Given that the ellipse x 2 / 4 + y 2 / 3 = 1 passes through the left focus of the ellipse and is parallel to the vector V = (1,1), the ellipse intersects two points a and B, and the length of the chord AB is calculated

Given that the ellipse x 2 / 4 + y 2 / 3 = 1 passes through the left focus of the ellipse and is parallel to the vector V = (1,1), the ellipse intersects two points a and B, and the length of the chord AB is calculated

Because a ^ 2 = 4, B ^ 2 = 3, so, C ^ 2 = a ^ 2-B ^ 2 = 1, then the left focus is (- 1,0), the equation of line AB is y = x + 1, substituting it into the elliptic equation to get x ^ 2 / 4 + (x + 1) ^ 2 / 3 = 1, simplifying to 7x ^ 2 + 8x-8 = 0, let a (x1, Y1), B (X2, Y2), then X1 + x2 = - 8 / 7, X1 * x2 = - 8 / 7, so | ab | ^ 2 = (x2-x