Help to calculate (2cos10 ° + sin20 °) / sin70 °

The original formula = [2cos10 ° - sin20 °] / (sin70 °) = [2cos10 ° - sin (30 ° - 10 °)] / (sin70 °) = [2cos10 ° - (sin30 ° cos10 - cos30 ° sin10 °)] / (sin70 °) = [(3 / 2) cos10 ° + (√ 3 / 2) sin10 ° [/ (sin70 °) = {√ 3 [...]

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