(-2)²ºº³+(-2)²ºº4 It's negative 2 to the power of 2003 plus negative 2 to the power of 2004
2 in 2003
You can pull a negative 2 by simplifying it for 2003 times
RELATED INFORMATIONS
- 1. If x and y are opposite to each other, m and N are reciprocal to each other, | a | = 2, find a & sup2; - (x + y + Mn) a + X & sup2; & ordm; & sup1; & sup1; + (- Mn) & sup2 If x and y are opposite to each other, m and N are reciprocal to each other, | a | = 2 Find the value of a & sup2; - (x + y + Mn) a + X & sup2; & ordm; & sup1; + (- Mn) & sup2; & ordm; & sup1; & sup1 During the national day, a shopping mall will offer preferential treatment to customers. The regulations are as follows: if a purchase does not exceed 200 yuan (including 200 yuan), 10% discount will be given according to the price; if a purchase exceeds 200 yuan but does not exceed 500 yuan (including 500 yuan), 20% discount will be given according to the price of all goods; if a purchase exceeds 500 yuan, 20% discount will be given except 500 yuan, If someone pays 162 yuan and 456 yuan respectively for two purchases, how much money can he save if he buys the same goods together? Sorry, I have the wrong number. Please forgive me a²-(x+y+mn)a+x²º¹¹+y²º¹¹+(-mn)²º¹¹
- 2. Calculation: 12 & sup1; & sup3;? (3 & sup1; & ordm; × 4 & sup1; & sup1;)
- 3. Given that a and B are opposite to each other, C and D are reciprocal to each other, and the absolute value of X is equal to 1, find the value of X & sup2; - (a + B + CD) x-cd
- 4. a. If B is opposite to each other, C and D are reciprocal to each other, and the absolute value of X is equal to twice of its opposite number, then x & sup2; + ABCD + (a + b) CD =?
- 5. It is known that in △ ABC, ∠ B is 20 ° larger than ∠ a, and ∠ B is 20 ° smaller than ∠ C. The degree of three internal angles in △ ABC can be calculated
- 6. In △ ABC, ∠ a - ∠ B = ∠ B - ∠ C = 15 °, find the degree of ∠ a ∠ B ∠ C
- 7. In the triangle ABC, the angle a-angle B = 60 ° and the angle B-angle C = 15 ° are used to find the degree of ∠ a ∠ B ∠ C
- 8. Given the degree ratio of the five outer angles of the Pentagon is 1:2:3:4:5, find the degree of the five inner angles of the Pentagon
- 9. In △ ABC, given ∠ a = 60 & ordm;, ∠ B ∶ C = 1 ∶ 5, find the degree of ∠ B
- 10. (a+b/a-b)² * 2a-2b/3a+3b - a²/a²-b² ÷ a/b
- 11. Help to calculate (2cos10 ° + sin20 °) / sin70 °
- 12. Calculation (- 4 / 3A & sup2; BC) / (- 3AB) × (- 7abc)
- 13. Given a / b = 1 / 3, calculate the value of a & sup2-2ab-b & sup2 / A & sup2-3ab + B & sup2
- 14. A & sup3; - 3A & sup2; B + 3AB & sup2; - B calculation a=-2 b=2
- 15. Calculation: 3A & sup3; B & sup2; △ A & sup2; + b * (A & sup2; b-3ab-5a & sup2; b)
- 16. A sin60 degree = 2sin30 degree B sin60 degree - sin45 degree = sin15 degree C 2sin30 degree cos 30 degree = sin60 degree D Tan 60 degree sin 60 degree = cos 60 degree
- 17. Calculate | 3-2 | - 12 × Tan 60 ° + 2cos 30 ° + (12) - 1
- 18. Calculation: Tan 60 ° + sin 245 ° - 2 cos 30 °
- 19. Calculation: tan60 ° + 2sin45 ° minus 2cos30 °=
- 20. What is the result of Tan 60 ° + 2tan 45 ° - 2cos 30?