It is known that in △ ABC, ∠ B is 20 ° larger than ∠ a, and ∠ B is 20 ° smaller than ∠ C. The degree of three internal angles in △ ABC can be calculated

Let ∠ B = x ∠ a be: x-20 ∠ C be: x + 20
X+X-20+X+20=180
3X=180
X=60
∠A=60-20=40° ∠C=60+20=80°

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