sin(a+30°)+cos(a+60°)2cosa=______ ．

Sin (a + 30 °) + cos (a + 60 °) 2cosa = sin (a + 30 °) + sin (90 °− a − 60 °) 2cosa = sin (a + 30 °) + sin (30 °− a) 2cosa = 2cos α sin30 ° 2cos α = 2sin30 ° = 1, so the answer is: 1

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