Acute trigonometric function 1. Simplification: | sin40 ° - 1 | + √ (1-cos ^ 240 °) 2. Assume 0 degree

Acute trigonometric function 1. Simplification: | sin40 ° - 1 | + √ (1-cos ^ 240 °) 2. Assume 0 degree

1. According to the definition of triangle sin40 〈 1: | sin40 ° - 1 | = 1-sin40 °
As above, cos ^ 240 ° is 1-sin ^ 240
According to the above two items, the original test = 1-sin40 ° + √ [1 - (1-sin240)]
＝1－sin40°＋√sin^2 40
＝1－sin40＋sin40＝1
2. If both sides of the equation are square, then sin ^ 2A * cos ^ 2A = 63 / 256 and sin ^ 2A + cos ^ 2A = 1
According to the above two terms, sin ^ 2A = 7 / 16 or 9 / 16
Sin a = √ 7 / 4 or 3 / 4
Because 0 degree