How to prove that f = xsinx is not a uniform continuous function on R? That is to say, it is proved that X and Y belong to R. when x approaches y, f (x) does not approach f (y) Could you give me a hint how to prove it?

How to prove that f = xsinx is not a uniform continuous function on R? That is to say, it is proved that X and Y belong to R. when x approaches y, f (x) does not approach f (y) Could you give me a hint how to prove it?

The uniformly continuous function is: as long as the independent variable | x1-x2 | ξ
Therefore, f = xsinx is not a uniformly continuous function on R