It is known that the function f (x) defined on R with the minimum positive period of 5 satisfies f (- x) = - f (x), And f (3) = 0, then in the interval (0,10), the number of solutions of the equation f (x) = 0 is?

It is known that the function f (x) defined on R with the minimum positive period of 5 satisfies f (- x) = - f (x), And f (3) = 0, then in the interval (0,10), the number of solutions of the equation f (x) = 0 is?

f(-3)=-f(3)=0
f(-3+5)=f(2)=f(-3)=0
f(2+5)=f(7)=0
f(3+5)=f(8)=0
So f (3), f (2), f (5), f (7) are all zero and have four solutions