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The results show that the value of - 2x & # 178; - 6x + 5 is not more than 19 / 2
-2x²-6x+5
=-2(x²+3x)+5
=-2(x+3/2)²+19/2
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- 11. Prove that the value of 2x ^ 2-6x + 11 is always greater than zero with matching method, and seek its minimum value, please! It is proved that the value of 2x ^ 2-6x + 11 is always greater than zero and its minimum value is obtained by matching method Is constant greater than zero the solution of this equation greater than zero Why am I 13 / 4? 2x^2-6x+11 =x^2-3x+11/2 =x^2-3x+(3/2)^2+11/2-(3/2)^2 =(x-3/2)^2+13/4 That's what I did
- 12. It is proved that the value of X & # 178; - 4x27 is greater than zero by matching method Solving x square + 2ax-b square + a square = 0 by collocation method If a, B satisfy a ^ B ^ + A ^ + B ^ + 10ab + 16 = 0 Finding the value of a and B
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- 18. It is proved by matching method that no matter what the value of X is, the value of 12x-3x & # 178; - 13X = 0 is always less than 0
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