Prove that the value of 2x ^ 2-6x + 11 is always greater than zero with matching method, and seek its minimum value, please! It is proved that the value of 2x ^ 2-6x + 11 is always greater than zero and its minimum value is obtained by matching method Is constant greater than zero the solution of this equation greater than zero Why am I 13 / 4? 2x^2-6x+11 =x^2-3x+11/2 =x^2-3x+(3/2)^2+11/2-(3/2)^2 =(x-3/2)^2+13/4 That's what I did

Prove that the value of 2x ^ 2-6x + 11 is always greater than zero with matching method, and seek its minimum value, please! It is proved that the value of 2x ^ 2-6x + 11 is always greater than zero and its minimum value is obtained by matching method Is constant greater than zero the solution of this equation greater than zero Why am I 13 / 4? 2x^2-6x+11 =x^2-3x+11/2 =x^2-3x+(3/2)^2+11/2-(3/2)^2 =(x-3/2)^2+13/4 That's what I did

2x^2-6x+11=2*(x-3/2)^2+13/2
The minimum is 13 / 2

Elden Ring Premiere

RELATED INFORMATIONS