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The maximum value of the square + 9 of the function y = x / 4x is What is the maximum value of the function y = x / {4 (square of x) + 9} (x > 0)? If 2a5 + 3a7 + 2a9 = 14, then S13 is equal to? It is known that the equation {x power of e} (SiNx + cosx) - a = 0 has a solution on the interval (0, π), then the value range of real number a is?
What is the maximum value of (x > 0) of the function y = x / {4 (square of x) + 9}? Y = 1 / (4x + 9 / x) mean value theorem x > 0 4x + 9 / x > = 2 √ (4x * 9 / x) = 12 denominator minimum value = 12, so the maximum value of y = 1 / 12, known arithmetic sequence an
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- 1. The maximum value of the function y = - x-4x + 9 is
- 2. The maximum value of the function f (x) = - x squared + 4x-7 is
- 3. The maximum value of quadratic function y = - 2x2 + 4x-9 is () A. 7B. -7C. 9D. -9
- 4. X square = 4x by factorization We use the factorization to solve the problem (1) 0xsquare = 4x (2) Xsquare - 2x + 1 = 4 (3) Square of 9 (x-1) = 4x square
- 5. Find X by the square of 4x + 4x + 1 = 0
- 6. The square of X - 4x + 1 = 0, find X
- 7. The square of x-4x-10 = 0
- 8. The square of x-4x-3596 = 0 Solving quadratic equation of one variable
- 9. (x's Square - 4x + 4) / (2x-6) / (x's square + X-6) / (12-4x) × (x + 3) / (1)
- 10. The square of X - 4x = 5
- 11. If x is greater than 0, then the maximum value of X squared + 2 / 4x is 0
- 12. If x.y satisfies x square + y square-4x + 1 = 0, find the maximum value of 3 / x, Y-X minimum value, x square + y square maximum value
- 13. X ∈ (0,1 / 4), then the maximum value of the square (1-4x) of y = x is-----
- 14. Find the square of x value (4x + 1) in the following formula - 1 = 7 / 9
- 15. How to solve (x + 1) square-2 (x-1) less than or equal to 4x
- 16. How to solve the problem that minus x square plus 4x equals 3
- 17. The results show that the value of - 2x & # 178; - 6x + 5 is not more than 19 / 2
- 18. Prove that the value of 2x ^ 2-6x + 11 is always greater than zero with matching method, and seek its minimum value, please! It is proved that the value of 2x ^ 2-6x + 11 is always greater than zero and its minimum value is obtained by matching method Is constant greater than zero the solution of this equation greater than zero Why am I 13 / 4? 2x^2-6x+11 =x^2-3x+11/2 =x^2-3x+(3/2)^2+11/2-(3/2)^2 =(x-3/2)^2+13/4 That's what I did
- 19. It is proved that the value of X & # 178; - 4x27 is greater than zero by matching method Solving x square + 2ax-b square + a square = 0 by collocation method If a, B satisfy a ^ B ^ + A ^ + B ^ + 10ab + 16 = 0 Finding the value of a and B
- 20. It is proved by collocation method that the value of - 4x + 27 is greater than zero and the value of - 6x & # 178; + 24x-25 is less than zero, It must be proved by matching method!