Given [- 2,3] of the domain of the function y = f (x + 1), then the domain of y = f (2x-1) is?
The questions are: - 2 ≤ x ≤ 3
Namely: - 1 ≤ x + 1 ≤ 4
For y = f (2x-1), there are: - 1 ≤ 2x-1 ≤ 4
That is: 0 ≤ x ≤ 5 / 2
That is, the domain of y = f (2x-1) is [0,5 / 2]
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