If f (x) = the square of X + BX + C, and f (1) = 0, f (3) = 0, find the value of F = (- 1) Use Chinese characters to express the idea of solving the problem, write it clearly, and adopt it immediately if it is correct!

If f (x) = the square of X + BX + C, and f (1) = 0, f (3) = 0, find the value of F = (- 1) Use Chinese characters to express the idea of solving the problem, write it clearly, and adopt it immediately if it is correct!

F (x) = x ^ 2 + BX + C from F (1) = 0, f (3) = 0 to get 1 + B + C = 0 (1) 9 + 3B + C = 0 (2) (2) minus (1) to get 2B + 8 = 0 = > B = - 4 from (1) formula C = - B - 1 = 4 - 1 = 3, so f (x) = x ^ 2 - 4x + 3, so f (- 1) = - 1) ^ 2 - 4 * (- 1) + 3 = 1 +