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If f (SiNx) = sin2x-sin3x, then f (cosx)= I just learned some formulas of induction function,
f(sinx)=2sinxcosx-sin2xcosx-cos2xsinx
=2sinx(1-sinx^2)^(1/2)-2sinx(1-sinx^2)-(1-2sinx^2)*sinx
So f (x) = 2x (1-x ^ 2) ^ (1 / 2) - 2x (1-x ^ 2) - (1-2x ^ 2) X
f(cosx)=2cosx(1-cosx^2）^(1/2)-2cosx(1-cosx^2)-(1-2cosx^2)cosx
=2cosxsinx-2cosxsinx^2+(2cosx^2-1)cosx
=sin2x-sin2xsinx+cos2xcosx
=sin2x+cos3x
RELATED INFORMATIONS
- 1. Finding f (cosx) by knowing f (SiNx) = sin3x RT
- 2. It is known that SiNx + cosx = - 1 / 5 (135 °)
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- 9. If SiNx = 2cosx, then SiNx cosx / SiNx + cosx=_____
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